Counting can be very hard at times.
Am I?Posted: Mon Mar 27 2017 01:20 pm

So, help.

http://imgur.com/a/JHj0S


Last Edited: Tue Mar 28 2017 09:35 am
FexSHOPosted: Tue Mar 28 2017 10:33 am

Hello,

because of the 4/3 and 1/3 on the left there cant be any 3s left for the horizontal 15 and the 22. Now you can put the missing 3 in the top of the vertical 10.

Further there must be a 6 in the bottom right, because if there would be a 7 or 8 there cant be a 3 at the horizontal 22.

(22 - 15 = 7; 7 must be 1,2 and 4 (and no 3))

This is a little bit laborious, but it works.


Am I?Posted: Wed Mar 29 2017 10:22 am

FexSHO wrote :

because of the 4/3 and 1/3 on the left there cant be any 3s left for the horizontal 15 and the 22. Now you can put the missing 3 in the top of the vertical 10.

You're a genius. This isn't laborious at all, this is fun.